Odpowiedź:
[tex]2 \times {10}^{15} \times 3 \times {10}^{7} = 6 \times {10}^{15} \times {10}^{7} = \\ 6 \times {10}^{15 + 7} = 6 \times {10}^{22} [/tex]
[tex] \sqrt[3]{ {5}^{2} } + \sqrt{2} = \sqrt[3]{25} + \sqrt{2} [/tex]
[tex] - {4}^{2} + ( { - 7})^{9} = - 16 + ( - 7) ^{9} = - 16 - {7}^{9} [/tex]
[tex]( {a}^{3} ) ^{5} \div ( {a}^{3} \times {a}^{5} ) = {a}^{15} \div ( {a}^{3 + 5 } ) = \\ {a}^{15} \div {a}^{8} = {a}^{7} [/tex]
[tex]( - 3x) ^{2} = ( - 3)^{2} \times {x}^{2} = 9 {x}^{2} [/tex]