[tex]t_{1}-czas \ w\ jakim\ Kasia\ pokonuje\ droge\ do\ szkoly\ z\ predkoscia\ 5\frac{km}{h} \\t_{2} -czas \ w\ jakim\ Kasia\ pokonuje\ droge\ do\ szkoly\ z\ predkoscia\ 6\frac{km}{h} \\4,5\ min=0,075h\\t_{1}-0,075h= t_{2} \\Wzor\ na\ predkosc:\\v=\frac{s}{t} \\v_{1} =5\frac{km}{h} \ \ v_{2} =6\frac{km}{h} \\\left \{ {{v_{1} =\frac{s}{t_{1} } } \atop {v_{2} =\frac{s}{t_{2} } \right.\\\left \{ {{5*t_{1}=s } \atop {6*(t_{1}-0,075) =s}} \right.\\\left \{ {{s=5t_{1} } \atop {6t_{1}-0,45 =5t_{1}}} \right.\\[/tex]
[tex]\left \{ {{s=5t_{1} } \atop {t_{1} =0,45}} \right.\\\\\left \{ {{s=5*0,45 } \atop {t_{1} =0,45}} \right.\\\\\left \{ {{s=2,25 } \atop {t_{1} =0,45}} \right.\\\\Odp.\ Kasia\ mieszka\ 2,25km\ od\ szkoly.[/tex]
