[tex]dane:\\m = 2 \ 200 \ kg\\\Delta T = 12^{o}C\\c = 4200\frac{J}{kg\cdot^{o}C}\\szukane:\\Q = ?\\\\Rozwiazanie\\\\Q = c\cdot m\cdot \Delta T\\\\Q = 4200\frac{J}{kg\cdot^{o}C}\cdot2200 \ kg\cdot12^{o}C\\\\Q = 110 \ 880 \ 000 \ J = 110 \ 880 \ kJ=110,88 \ MJ\\\\\\1 \ kJ = 1000 \ J\\1 \ MJ = 1 \ 000 \ 000 \ J[/tex]
