[tex]Zadanie\\\\d=\frac{xa}{x-a}\ \ \mid\cdot(x-a)\\\\d(x-a)=xa\\\\dx-ad=xa\ \ \mid+ad\\\\ dx= xa+ad\\\\dx=a(x+d)\ \ \mid:(x+d)\\\\\frac{dx}{x+d} =a\\\\a=\frac{dx}{x+d}\\\\\\Zal.\\ x+d\ne0[/tex]
