Obliczenia :
[tex](5\frac{1}{4}-2\frac{3}{4})+(5\frac{3}{12}-1\frac{9}{12})+(10\frac{3}{10}-8\frac{8}{10})=\\\\=(4\frac{5}{4}-2\frac{3}{4})+(4\frac{15}{12}-1\frac{9}{12})+(9\frac{13}{10}-8\frac{8}{10})=\\\\=2\frac{2}{4}+3\frac{6}{12}+1\frac{5}{10}=2\frac{1}{2}+3\frac{1}{2}+1\frac{1}{2}=6\frac{3}{2}=\boxed{7\frac{1}{2}}[/tex]
