[tex]dane:\\C_{p_1} = 5\%\\m_{r_1} = 150 \ g\\C_{p_2} = 8\%\\m_{r_2} = 400 \ g\\szukane:\\C_{p} = ?\\\\Rozwiazanie\\\\m_{s_1} = \frac{C_{p_1}\cdot m_{r_1}}{100\%} = \frac{5\%\cdot600 \ g}{100\%} = 30 \ g\\\\m_{s_2} = \frac{C_{p_2}\cdot m_{r_2}}{100\%}=\frac{8\%\cdot400 \ g}{100\%} = 32 \ g\\\\C_{p} = \frac{m_{s}}{m_r}}\cdot100\% = \frac{30 \ g+32 \ g}{600 \ g + 400 \ g}\cdot100\% = \frac{62 \ g}{1000 \ g}\cdot100\% = 6,2\%[/tex]
Odp. Stężenie otrzymanego roztworu wynosi 6,2%.
