Zadanie 2.
[tex]P = \frac{(a+b)*h}{2}[/tex]
a) h = 4 cm
a = 10 cm
b = a + 5 cm = 10 cm + 5 cm = 15 cm
[tex]P=\frac{(10 \ cm \ + \ 15 \ cm) \ * \ 4 \ cm}{2} = \frac{25 \ cm \ * \ 4 \ cm}{2} = \frac{100 \ cm^2}{2} = 50 \ cm^2[/tex]
Odp. Pole trapezu wynosi 50 cm².
b) a + b = 7 cm
h = 4 cm
[tex]P = \frac{7 \ cm \ * \ 4 \ cm}{2} = \frac{28 \ cm^2}{2} = 14 \ cm^2[/tex]
Odp. Pole trapezu wynosi 14 cm².
