2*2^7+2^3*2^5=2^8+2^8=2^9
a
zad 2
[tex]\sqrt{2}*\sqrt{8}+\sqrt{12}*\sqrt{3}=\sqrt{16}+\sqrt{36}=4+6=10[/tex]
[tex]0,5*(\sqrt{20})^{2}=0,5*20=10[/tex]
d
zad 3
pole rombu= pole boku * wysokość
[tex]15\sqrt{3}=a*5/:\\3\sqrt{3}=a[/tex]
