Odpowiedź:
według mnie to będzie wyglądało tak
a)
[tex]3 \sqrt{75 } \div \sqrt{3} = 3 \sqrt{75 \div 3} = 3 \sqrt{25} = 3 \times 5 = 15[/tex]
b)
[tex]2 \sqrt[3]{24} \div \sqrt[3]{3} = 2 \sqrt[3]{24 \div 3} = 2 \sqrt[3]{8} = 2 \times 2 = 4[/tex]
c)
[tex]3 \sqrt[3]{4} \times 5 \sqrt[3]{2} = 3 \times 5 \sqrt[3]{4 \times 2} = 15 \sqrt[3]{8} = 15 \times 2 = 30[/tex]
d)
[tex] \frac{4 \sqrt{10} \times \sqrt{5} }{5 \sqrt{2} } = \frac{4 \sqrt{10 \times 5} }{5 \sqrt{2} } = \frac{4 \sqrt{50} }{5 \sqrt{2} } = \frac{4 \times 5 \sqrt{2} }{5 \sqrt{2} } = 4[/tex]
e)
[tex]7 \sqrt{8} \times \frac{6 \sqrt{3} }{ \sqrt{6} } = \frac{7 \sqrt8 \times 6 \sqrt{3} }{ \sqrt{6} } = \frac{7 \times 6 \sqrt{8 \times 3} }{ \sqrt{6} } = \frac{42 \sqrt{24} }{ \sqrt{6} } = 42 \sqrt{24} \div \sqrt{6 } = 42 \sqrt{24 \div 6} = 42 \sqrt{4} = 42 \times 2 = 48[/tex]
f)
[tex] \frac{ \sqrt[3]{24} }{6 \sqrt[3]{3} } = \sqrt[3]{24} \div 6 \sqrt[3]{3} = \frac{1}{6} \sqrt[3]{24 \div 3} = \frac{1}{6} \sqrt[3]{8} = \frac{1}{6} \times 2 = \frac{2}{6} = \frac{1}{3} [/tex]
g)
[tex] \frac{ \sqrt[3]{9} \times 2 \sqrt[3]{6} }{3 \sqrt[3]{2} } = \frac{2 \sqrt[3]{9 \times 6} }{3 \sqrt[3]{2} } = \frac{2 \sqrt[3]{54} }{3 \sqrt[3]{2} } = 2 \sqrt[3]{54} \div 3 \sqrt[3]{2} = \frac{2}{3} \sqrt[3]{54 \div 2} = \frac{2}{3} \sqrt[3]{27} = \frac{2}{3} \times 3 = \frac{6}{3} = 2[/tex]
h)
[tex] \frac{4 \sqrt{6} \times 2 \sqrt{3} }{3 \sqrt{2} } = \frac{4 \times 2 \sqrt{6 \times 3} }{3 \sqrt{2} } = \frac{8 \sqrt{18} }{3 \sqrt{2} } = 8 \sqrt{18} \div 3 \sqrt{2} = \frac{8}{3} \sqrt{18 \div 2} = \frac{8}{3} \sqrt{9} = \frac{8}{3} \times 3 = \frac{24}{3} = 6[/tex]
