Odpowiedź :
a)
obw: 5+5+5=15cm
P a • h
h = 5√3/2
P = 5 • 5√3/2 = 25√3/2 = 12,5√3
b)
obw 5+5+6=16cm
h= 6√3/2 = 3√3
P 6 • 3√3 = 18√3
C)
[tex]9 {}^{2} = 4 \sqrt{3 {}^{2} } + \times {}^{2} [/tex]
81=12+ x^2
x^2 = 81 -12 = 69
[tex] \times = \sqrt{69} [/tex]
P:
[tex] \sqrt{69} \times 4 \sqrt{3} = 12 \sqrt{23} [/tex]