[tex]dane:\\h = 5 \ m\\E_{p} = 2 \ J\\g = 10\frac{m}{s^{2}}\\szukane:\\m = ?\\\\E_{p} = mgh \ \ /:gh\\\\m = \frac{E_{p}}{gh}=\frac{2 \ J}{10\frac{m}{s^{2}}\cdot5 \ m} = \frac{2\ kg\cdot\frac{m^{2}}{s^{2}}}{50 \ \frac{m^{2}}{s^{2}}} = 0,04 \ kg=4 \ dag= 40 \ g[/tex]
