Zad.1.5
[tex]6\frac{2}{5}+6\frac{2}{5}+1\frac{1}{4}+6\frac{2}{5}+1\frac{1}{4}+1\frac{1}{4}+6\frac{2}{5}+1\frac{1}{4}+1\frac{1}{4}+1\frac{1}{4}=4*6\frac{2}{5}+6*1\frac{1}{4}=\\24\frac{8}{5}+6\frac{3}{2}=25\frac{6}{10}+7\frac{5}{10}=32\frac{11}{10}=33\frac{1}{10}[/tex]
Zad.1.6
[tex]65\frac{1}{2}+65\frac{1}{2}-5\frac{1}{3}+65\frac{1}{2}-5\frac{1}{3}-5\frac{1}{3}+65\frac{1}{2}-5\frac{1}{3}-5\frac{1}{3}-5\frac{1}{3}+65\frac{1}{2}-5\frac{1}{3}-5\frac{1}{3}-5\frac{1}{3}-5\frac{1}{3}=\\5*65\frac{1}{2}-10*5\frac{1}{3}=325\frac{5}{2}-50\frac{10}{3}=327\frac{3}{6}-53\frac{2}{6}=274\frac{1}{6}[/tex]
Zad.1.7
[tex]24\frac{1}{4}-4\frac{1}{2}+24\frac{1}{4}+24\frac{1}{4}+4\frac{1}{2}=3*24\frac{1}{4}=72\frac{3}{4}[/tex]
Zad.1.8
[tex]10\frac{3}{4}+10\frac{3}{4}-3\frac{1}{2}+2( 10\frac{3}{4}-3\frac{1}{2}-1\frac{2}{5})=\\20\frac{6}{4}-3\frac{1}{2}+2(10\frac{15}{20}-3\frac{10}{20}-1\frac{8}{20})=\\20\frac{3}{2}-3\frac{1}{2}+2*5\frac{17}{20}=17\frac{2}{2}+10\frac{34}{20}=18+11\frac{14}{20}=18+11\frac{7}{10}=29\frac{7}{10}[/tex]
Zad.1.9
[tex]3\frac{1}{3}+22\frac{1}{4}-(13\frac{1}{3}-6\frac{1}{4})=3\frac{1}{3}+22\frac{1}{4}-13\frac{1}{3}+6\frac{1}{4}=\\-10+28\frac{2}{4}=18\frac{1}{2}[/tex]
Zad.1.10
[tex]15\frac{5}{6}-8\frac{1}{8}+3\frac{3}{4}+4\frac{2}{3}=\\15\frac{1}{6}+4\frac{4}{6}-8\frac{1}{8}+3\frac{6}{8}=19\frac{5}{6}-4\frac{3}{8}=19\frac{40}{48}-4\frac{18}{48}=15\frac{22}{48}=15\frac{11}{24}[/tex]
Zad.1.11
[tex]24\frac{3}{7}-5\frac{1}{3}-(3\frac{1}{7}+1\frac{1}{2}+5\frac{1}{6})=\\24\frac{3}{7}-5\frac{2}{6}-3\frac{1}{7}-1\frac{3}{6}-5\frac{1}{6}=\\21\frac{2}{7}-12=9\frac{2}{7}[/tex]
Zad.1.12
[tex]a)\\3\frac{1}{2}+(1\frac{1}{3}+x)=6\ |*6\\21+8+6x=36\\6x+29=36\ |-29\\6x=7\ |:6\\x=1\frac{1}{6}\\[/tex]
[tex]b)\\x-(7\frac{1}{3}+2\frac{3}{5})=3\frac{1}{4}\ |*60\\60x-440-156=195\\60x-596=195\ |+596\\60x=791\ |:60\\x=13\frac{11}{60}\\[/tex]
[tex]c)\\17\frac{1}{2}-(9\frac{1}{3}+x)=4\frac{1}{4}\ |*12\\210-112-12x=51\\-12x+98=51\ |-98\\-12x=-47\ |:(-12)\\x=3\frac{11}{12}[/tex]
[tex]d)\\(2\frac{3}{4}+4\frac{1}{6})-(x-4\frac{1}{2})=5\ |*12\\33+50-12x+54=60\\-12x+137=60\ |-137\\-12x=-77\ |:(-12)\\x=6\frac{5}{12}[/tex]
