Odpowiedź :
Odpowiedź:
zad 1
C = ( 4 , - 2 ) , D = ( 0 , 5 )
xc = 4 , xd = 0 , yc = - 2 , yd = 5
ICDI = √[(xd - xc)² + (yd - yc)²] = √[(0 - 4)² + (5 + 2)²] = √[(- 4)² + 7²] =
= √(16 + 49) = √65
zad 2
A = ( 2 , 7 ) , B = ( - 4 , - 8 )
xa = 2 , xb = - 4 , ya = 7 , yb = - 8
S = (xs , ys)
xs = (xa + xb)/2 = (2 - 4)/2 = - 2/2 = - 1
ys = (ya + yb)/2 = ( 7 - 8)/2 = - 1/2
S = ( - 1 , - 1/2 )
[tex]Zadanie\ 1\\\\\mid CD\mid=\sqrt{(x_D-x_C)^2+(y_D-y_C)^2}\\\\\mid CD\mid= \sqrt{(0-4)^2+[5-(-2)]^2}=\sqrt{(-4)^2+7^2}=\sqrt{16+49}=\sqrt{65}\\\\\\Zadanie\ 2\\\\ S=\((\frac{x_A+x_B}{2}\ ;\ \frac{y_A+y_B}{2})\\\\S=(\frac{2+(-4)}{2}\ ;\ \frac{7+(-8)}{2}) \\\\S=( \frac{-2}{2}\ ;\ \frac{-1}{2})\\\\S=(-1\ ;\ -\frac{1}{2})[/tex]