Rozwiązanie równania :
[tex]2(x+1)^2=5(4-x)\\\\2(x^2+2x+1)=20-5x\\\\2x^2+4x+2-20+5x=0\\\\2x^2+9x-18=0\\\\a=2, \ b=9, \ c=-18\\\\\Delta=b^2-4ac\rightarrow9^2-4\cdot2\cdot(-18)=81+144=225\\\\\sqrt{\Delta}=\sqrt{225}=15\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}\rightarrow\frac{-9-15}{2\cdot2}=\frac{-24}{4}=\boxed{-6}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}\rightarrow\frac{-9+15}{2\cdot2}=\frac{6}{4}=\boxed{1,5}[/tex]
