[tex]dane:\\m = 900 \ kg\\v = 40\frac{km}{h} = 40\cdot\frac{1000 \ m}{3600 \ s} = 11,(1)\frac{m}{s} = 11,11\frac{m}{s}\\r = 50 \ m\\szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\F_{d} = \frac{mv^{2}}{r}\\\\F_{d} = \frac{900 \ kg\cdot(11,11\frac{m}{s})^{2}}{50 \ m} \approx2 \ 222 \ N \approx 2,222 \ kN[/tex]
