Odpowiedź :
1)
[tex]6x + 4 = 5x - 3\\\\6x - 5x = -3-4\\\\x = -7[/tex]
2)
[tex]4(x+3) = 3x+2\\\\4x+12 = 3x + 2\\\\4x-3x = 2-12\\\\x = -10[/tex]
3)
[tex](15-x) - (14-2x) = 1+x\\\\15-x-14+2x = 1 + x\\\\-x+2x-x = 1-15+14\\\\0 = 0[/tex]
Równanie tożsamościowe, nieskończenie wiele rozwiązań.
4)
[tex]\frac{x}{4}-\frac{x}{8} = 6 + \frac{x}{2} \ \ /\cdot8\\\\2x-x = 48 + 4x\\\\x-4x = 48\\\\-3x = 48 \ \ /:(-3)\\\\x = -16[/tex]
5)
[tex]\frac{1}{2}=x-\frac{2x+1}{3} \ \ /\cdot6\\\\3 = 6x - 2(2x+1)\\\\3 = 6x - 4x - 2\\\\3 = 2x-2\\\\-2x = -2-3\\\\-2x=-5 \ \ /:(-2)\\\\x = 2\frac{1}{2} = 2,5[/tex]
6)
[tex](x^{2}-6) - 5(x+6) = x(x-5)-7x-x(x-7)\\\\x^{2}-6-5x-30 = x^{2}-5x-7x-x^{2}+7x\\\\x^{2}-5x-36 = -5x\\\\x^{2}-36 = 0\\\\(x+6)(x-6) = 0\\\\x = -6 \ \vee \ x = 6[/tex]