Odpowiedź:
1) d = 12[tex]\sqrt{2[/tex] 2) a) h = [tex]5 \sqrt{3}[/tex] P = [tex]25\sqrt{3[/tex] b) h = [tex]3\sqrt{6[/tex] P = [tex]18\sqrt{3[/tex]
Szczegółowe wyjaśnienie:
1)
d = a[tex]\sqrt{2[/tex]
d = 12[tex]\sqrt{2[/tex]
2)
a)
h = [tex]\frac{a\sqrt{3} }{2}[/tex]
h = [tex]\frac{10\sqrt{3} }{2} = 5\sqrt{3[/tex]
P = [tex]\frac{a^2\sqrt{3} }{4}[/tex]
P = [tex]\frac{10^2\sqrt{3} }{4} = 25\sqrt{3}[/tex]
b)
h = [tex]\frac{6\sqrt{2}\sqrt{3} }{2} = 3\sqrt{6}[/tex]
P = [tex]\frac{(6\sqrt{2^2)}\sqrt{3} }{4} = \frac{36 * 2 * \sqrt{3}}{4} = \frac{72\sqrt{3} }{4} = 18\sqrt{3}[/tex]
