Proszę o pomoc potrzebuję do dziś

a) 8cm : 2 = 4 cm
[tex]4^{2}[/tex] + [tex]h^{2}[/tex] = [tex]5^{2}[/tex]
16 + [tex]h^{2}[/tex] = 25
[tex]h^{2}[/tex] = 25 - 16
[tex]h^{2}[/tex] = 9
h = [tex]\sqrt{9}[/tex]
h = 3
P =[tex]\frac{ah}{2}[/tex] = [tex]\frac{8x3}{2}[/tex] = 4 cm x 3 cm = 12 [tex]cm^{2}[/tex]
b) 10 cm : 2 = 5 cm
[tex]5^{2}[/tex] + [tex]h^{2}[/tex] = [tex]13^{2}[/tex]
25 + [tex]h^{2}[/tex] = 169
[tex]h^{2}[/tex] = 169 - 25
[tex]h^{2}[/tex] = 144
h = [tex]\sqrt{144}[/tex]
h = 12
P = [tex]\frac{ah}{2}[/tex] = [tex]\frac{10x12}{2}[/tex] = 10 cm x 6 cm = 60[tex]cm^{2}[/tex]
c) 8 cm : 2 = 4 cm
[tex]4^{2}[/tex] + [tex]h^{2}[/tex] = [tex]6^{2}[/tex]
16 + [tex]h^{2}[/tex] = 36
[tex]h^{2}[/tex] = 36 - 16
[tex]h^{2}[/tex] = 20
h = [tex]\sqrt{20}[/tex]
h = 2[tex]\sqrt{5}[/tex]
P = [tex]\frac{ah}{2}[/tex] = [tex]\frac{8x2\sqrt{5} }{2}[/tex] = 8cm x [tex]\sqrt{5}[/tex]cm = 8[tex]\sqrt{5}[/tex][tex]cm^{2}[/tex]
a) obliczamy wysokość(h) z pitagorasa czyli:
h^= 5^ - 4^= 9 - teraz pierwiastkujemy
h= 3
P= 8*3/2 = 12 cm^
b) h^= 13^ - 5^ = 169-25 =144
h= 12cm
P= 12*10/2 = 60 cm^
c) h^= 6^-4^ = 36-16 =20
h= 2pierwiatski z 5
P= 2pier5* 8/2 = 8 pier. 5 cm^
Powinno być dobrze ;)