[tex]x(x-8)-6(x+1)+(x^{2}-3) = x(x-6)-8x\\\\x^{2}-8x -6x - 6 + x^{2}-3 = x^{2}-6x-8x\\\\2x^{2}-14x - 9 = x^{2}-14x\\\\2x^{2}-x^{2}-14x+14x-9 = 0\\\\x^{2}-9 =0\\\\(x+3)(x-3) = 0\\\\x+3 = 0 \ \vee \ x -3 = 0\\\\x = -3 \ \vee \ x =3\\\\x \in \{-3; 3\}[/tex]
