Odpowiedź:
zad.1 d₁=10cm
d₂=14cm
½d₁=5cm
½d₂=7cm
a=bok rombu
a=√[5²+7²]=√74
sinα=5/√74=5√74/74
tgα=5/7
cos α=7/√74=7√74/74
ctgα=7/5
sinβ=7/√74=7√74/74
cosβ=5/√74=5√74/74
tgβ=7/5
ctgβ=5/7
zad.2
[tex]a) (\frac{\sqrt{2} }{2} )^2-(\frac{\sqrt{3} }{2} )^2+(\frac{1}{2})^2=\frac{2}{4} -\frac{3}{9} +\frac{1}{4}=\frac{5}{12} \\\b) (\frac{\sqrt{3} }{2})^2-1^2+(\frac{\sqrt{3} }{2})^2=2*(\frac{\sqrt{3} }{2})^2-1=2*\frac{3}{4}-1=\frac{3}{2}-1=\frac{1}{2}[/tex]
Szczegółowe wyjaśnienie:
