[tex]dane:\\d = 700\frac{kg}{m^{3}}\\h = 0,3 \ m\\g = 10\frac{m}{s^{2}} = 10\frac{N}{kg}\\szukane:\\p = ?\\\\p = d\times g\times h\\\\p = 700\frac{kg}{m^{3}}\times10\frac{N}{kg}\times0,3 \ m\\\\p = 2 \ 100 \ \frac{N}{m^{2}} = 2 \ 100 \ Pa = 21 \ hPa = 2,1 \ kPa\\\\\\1 \ hPa = 100 \ Pa\\1 \ kPa = 1000 \ Pa[/tex]
