[tex]dane:\\v_{o} = 0\\v = 10\frac{m}{s}\\g = 10\frac{m}{s^{2}}\\szukane:\\h = ?[/tex]
Z zasady zachowania energii
[tex]E_{p} = E_{k}\\\\mgh = \frac{mv^{2}}{2} \ \ /:mg\\\\h = \frac{v^{2}}{2g}\\\\h = \frac{(10\frac{m}{s})^{2}}{2\cdot10\frac{m}{s^{2}}} = \frac{100\frac{m^{2}}{s^{2}}}{20\frac{m}{s^{2}}} = 5 \ m[/tex]
