[tex]dane:\\m = 5 \ kg\\h = 2 \ m\\t = 5 \ s\\g = 10\frac{m}{s^{2}}\\szukane:\\P = ?\\\\Rozwiazanie\\\\P = \frac{W}{t}\\\\ale:\\\\W = E_{p} = mgh\\\\P = \frac{mgh}{t}\\\\P = \frac{5 \ kg\cdot10\frac{m}{s^{2}}\cdot2 \ m}{5 \ s} = 20 \ W[/tex]
Odp. Moc Kasi P = 20 W.
