Odpowiedź:
(x - 3)/(x + 2) + (x + 4)/(x - 1)
założenie:
x + 2 ≠ 0 ∧ x - 1 ≠ 0
x ≠ - 2 ∧ x ≠ 1
D: x ∈ R \ {- 2 , 1 }
(x - 3)/(x + 2) + (x + 4)/(x - 1) = [(x - 3)(x - 1) + (x + 4)(x + 2)]/[(x + 2)(x - 1)] =
= (x² - 3x - x + 3 + x² + 4x + 2x + 8)/(x² + 2x - x - 2) =
= (2x² + 2x + 11)/(x² +x - 2)
