Obliczenia :
[tex]a] \ \sqrt[3]{-125}=\sqrt[3]{(-5)^3}=-5\\\\b] \ 2\cdot\sqrt{16}=2\cdot\sqrt{4^2}=2\cdot4=8\\\\c] \ -5+\sqrt{49}=-5+\sqrt{7^2}=-5+7=2\\\\d] \ (\frac{2\sqrt3}{5})^2}=\frac{2^2\cdot(\sqrt3)^2}{5^2}=\frac{4\cdot3}{25}=\frac{12}{25}\\\\e] \ \frac{2\sqrt[3]{5^3}}{\sqrt{6^2}}=\frac{2\cdot5}{6}=\frac{10}{6}=\frac{5}{3}=1\frac{2}{3}\\\\f] \ -2+\sqrt7\cdot\sqrt7=-2+\sqrt{7^2}=-2+7=5[/tex]
