Odpowiedź:
[tex]2 \sqrt{32} + 4 \sqrt{2} = {2}^{3} \sqrt{2} + 4 \sqrt{2} = \\ 8 \sqrt{2} + 4 \sqrt{2} = 12 \sqrt{2} [/tex]
[tex] \sqrt{45} - \sqrt{5} = 3 \sqrt{5} - \sqrt{5} = 2 \sqrt{5} [/tex]
[tex]2 \sqrt{27} + \sqrt{12} = 6 \sqrt{3} + 2 \sqrt{3} = 8 \sqrt{3} [/tex]
[tex]7 \sqrt{32} - 2 \sqrt{18} = 7 \times {2}^{2} \sqrt{2} - 6 \sqrt{2} = \\ 7 \times 4 \sqrt{2} - 6 \sqrt{2} = 28 \sqrt{2} - 6 \sqrt{2} = 22 \sqrt{2} [/tex]
[tex]2 \sqrt[3]{81} + \sqrt[3]{24} = 6 \sqrt[3]{3} + 2 \sqrt[3]{3} = 8 \sqrt[3]{3} [/tex]
[tex]7 \sqrt[3]{16} - 2 \sqrt[3]{54} = 14 \sqrt[3]{2} - 6 \sqrt[3]{2} = 8 \sqrt[3]{2} [/tex]
