Odpowiedź:
c)
[tex]\frac{x^{2} +8}{x^{2} - 4} = 2\\x^{2} -4 \neq 0\\x\neq 2 lub x\neq -2\\[/tex]
x ∈ R / {-2; 2}
[tex]\frac{x^{2} +8}{x^{2} -4} =2\\x^{2} +8 = 2(x^{2} -4)\\x^{2} +8 = 2x^{2} -8\\-x^{2} = - 16\\x^{2} = 16\\\\x = 4\\lub\\x = -4[/tex]
d)
[tex]\frac{-3x^{2} +2x}{x^{2} +4}= -3 \\x^{2} +4 \neq 0\\x\neq 2\\lub\\x\neq -2\\[/tex]
x ∈ R / {-2; 2}
[tex]\frac{-3x^{2} +2x}{x^{2} +4} =-3[/tex]
[tex]-3x^{2} +2x = -3(x^{2} +4)\\-3x^{2} +2x = -3x^{2} -12\\2x = -12\\x = -6[/tex]
