5.
[tex]dane:\\F_{c} = 2,2 \ kN\\F_{T} = 0,6 \ kN\\F_{o} = 0,4 \ kN\\szukane:\\F_{w} = ?\\\\F_{w} = F_{c} - (F_{T} + F_{o})\\\\F_{w} = 2,2 \ kN - (0,6 \ kN + 0,4 \ kN)\\\\F_{w} = 2,2 \ kN - 1 \ kN = 1,2 \ kN\\\\Odp. \ D.[/tex]
6.
[tex]dane:\\F_{w} = 1,2 \ kN = 1 \ 200 \ N\\a = 1\frac{m}{s^{2}}\\szukane:\\m = ?\\\\a = \frac{F_{w}}{m} \ \ \rightarrow \ \ m = \frac{F_{w}}{a}\\\\m = \frac{1200 \ N}{1\frac{m}{s^{2}}} = \frac{1200 \ kg\cdot\frac{m}{s^{2}}}{1\frac{m}{s^{2}}} = 1200 \ kg = 1,2 \ t\\\\Odp. \ A.[/tex]
