Odpowiedź:
A
[tex] {3}^{2} + 2 \times 3 \times \frac{1}{3} - 8 \frac{1}{3} = 9 + 6 \times \frac{1}{3} - 8 \frac{1}{3} = 9 + 2 - 8 \frac{1}{3} =2 \frac{2}{3} [/tex]
B
C
[tex]18 \times \frac{1}{9} \times \frac{1}{2} - 5 \times { \frac{1}{9} }^{2} + 3 \frac{1}{2} = 18 \times \frac{1}{9} \times \frac{1}{2} - 5 \times \frac{1}{81} = 2 \times \frac{1}{2} - 5 \times \frac{1}{81} = 1 - 5 \times \frac{1}{81} = 1 - \frac{5}{81} = \frac{76}{81} [/tex]
