[tex]dane:\\m = 2 \ kg\\v = 15\frac{m}{s}\\t = 2 \ s\\szukane:\\P = ?\\\\Rozwiazanie\\\\P = \frac{W}{t}\\\\ale \ \ W = E_{k} = \frac{1}{2}mv^{2}}\\\\W = \frac{1}{2}mv^{2} = \frac{1}{2}\cdot2 \ kg\cdot(15\frac{m}{s})^{2} = 225 \ J\\\\P = \frac{W}{t} =\frac{225 \ J}{2 \ s} = 112,5 \ W[/tex]
Odp. Moc tego piłkarza P = 112,5 W.
