Odpowiedź:
a. [tex]\frac{1}{3}x-2=x+2[/tex]
x - 6 = 3x + 6
x - 3x = 6 + 6
-2x = 6 + 6
- 2x = 12
x = -6
b. [tex]1-\frac{6}{7} x=\frac{4}{7}[/tex]
7 - 6x = 4
-6x = 4 - 7
-6x = -3
x = [tex]\frac{1}{2}[/tex]
c. [tex]6(\frac{1}{4}x-2)=18[/tex]
[tex]\frac{1}{4} x - 2 = 3[/tex]
x - 8 = 12
x = 12 + 8
x = 20
d. [tex]\frac{x}{6} - \frac{1}{6} = 1[/tex]
x - 1 = 6
x = 6 + 1
x = 7
e. [tex]-2(2x-1)=\frac{x}{3}[/tex]
-4x + 2 = [tex]\frac{x}{3}[/tex]
-12x + 6 = x
-12x - x =-6
-13x = - 6
x = [tex]\frac{6}{13}[/tex]
f. [tex]\frac{2}{5} * (3-x) =-2[/tex]
3 - x = -5
-x = -5 - 3
-x = - 8
x = 8
g. [tex]\frac{3}{4} * (2-3x) = -6\\[/tex]
2 - 3x = -8
-3x = -8 - 2
-3x = -10
x = [tex]\frac{10}{3}[/tex]
h. [tex]\frac{1}{5} * (x-3) = 9-x \\[/tex]
x - 3 = 45 - 5x
x + 5x = 45 + 3
6x = 48
x = 8
bez i bo nie umiem, sorki
licze na naaj
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