Odpowiedź:
[tex]1.\\\sqrt{27} = \sqrt{9*3} = 3\sqrt{3} \\\sqrt{7^{3} } = 7\sqrt{7} \\\sqrt[3]{500} = \sqrt[3]{125*4} = 5\sqrt[3]{4} \\\sqrt[3]{6^{5} } = 6\sqrt[3]{36} \\[/tex]
[tex]2.\\A. \sqrt{17 + 3} = 2\sqrt{5} -- poprawnie\\B. \sqrt{\frac{9}{100} } = \frac{3}{10} -- poprawnie\\C. \sqrt{25+81} = \sqrt{106} -- niepoprawnie X\\D. \sqrt{81*5} = 9\sqrt{5} -- poprwnie[/tex][tex]3.\\a) \sqrt{64} +\sqrt[3]{100} = 8 + 10 = 18\\b) \sqrt[3]{7^{2}+15 } = \sqrt[3]{49+15} = \sqrt[3]{64} = 4\\c) \sqrt{13^{2} } + \sqrt[3]{7^{3} } = 13 + 7 = 20\\d) \sqrt{2} * \sqrt{18} +3* \sqrt[3]{3} * \sqrt[3]{9} = \sqrt{36} + 3\sqrt[3]{27} = 6 +3 *3 = 6+9=15\\e) \frac{\sqrt{75 }+2\sqrt{3} }{\sqrt{3} } = \frac{5\sqrt{3} + 2\sqrt{3} }{\sqrt{3} } = 7[/tex][tex]4.\\a)\\b) \\c) \sqrt[3]{500} + \sqrt[3]{-108} = \sqrt[3]{125*4} + \sqrt[3]{-27* 4} = 5\sqrt[3]{4} - 3\sqrt[3]{4} = 2\sqrt[3]{4}[/tex]
