Odpowiedź:
wzory! : 0bw koła = 2πr lub πd; Pole = πr²
a) obw = 6π
6π = 2πr /:π
6 = 2r
3 = r
P = π * 3² = 9π
b) obw = 5π
5π = 2πr /:π
5 = 2r
2,5 = r
P = π * 2,5² = 6,25π
c) obw = π
π = 2πr /:2π
1/2 = r
P = π * (1/2)²= 1/4π
d) obw = 1
1 = 2πr / :2π
1/2π = r
P = π * (1/2π)² = π * 1/ 4π² = 1/4π
Szczegółowe wyjaśnienie:
Moge naj ?