Odpowiedź:
[tex]sin45 = \frac{h}{4} \\\frac{\sqrt{2} }{2} = \frac{h}{4} \\2h = 4\sqrt{2} \\h = 2\sqrt{2}[/tex]
h = a
[tex]P = \frac{1}{2} ah\\P=\frac{1}{2} *2\sqrt{2}*2\sqrt{2}\\P = \sqrt{2} * 2\sqrt{2} \\P = \sqrt{2} * \sqrt{8} \\P = \sqrt{16} \\P = 4cm^2[/tex]
[tex]Obw = 4 + 2\sqrt{2} + 2\sqrt{2} \\Obw = 4+ 4\sqrt{2} cm[/tex]
