Odpowiedź:
[tex]0 = 1+ a+ b+ c = W (1)\\W (x) = (x - m) (x - m - 3) (x - m - 6)\\0= W (1) = (1 - m) (1 - m - 3) (1-m-6)\\0=(m-1) (m+2)(m+5)\\m=1 ---> (1,4,7)\\m=-2 ---> (-2,1,4)\\m=-5 ---> (-5, -2,1)\\(x-1)(x-4)(x-7)=(x^{2} - 5x+4)(x-7) = x^{3} - 12x^{2} +39x-28\\(x+2)(x-1)(x-4)=(x^{2} +x-2)(x-4)=x^{3} -3x^{2} -6x+8\\(x+5)(x+2)(x-1)=(x^{2}+7x+10)(x-1) = x^{3} +6x^{2} +3x-10[/tex]
