Szczegółowe wyjaśnienie:
Zad 6
[tex]a)10 \sqrt{2} + 1 \\ b)7 \sqrt{3} - 2 \\ c)3 \sqrt[3]{7} - 4 \\ d)2 \sqrt[3]{6} + 5[/tex]
Zad 7
[tex]a) \sqrt{1 } = 1 \\ \sqrt{4} = 2 \\ \sqrt{9} = 3 \\ \sqrt{16} = 4 \\ \sqrt{25} = 5 \\ \sqrt{36} = 6 \\ \sqrt{49} = 7 \\ \sqrt{64} = 8 \\ \sqrt{81} = 9 \\ \sqrt{100} = 10 \\ \sqrt{121} = 11 \\ \sqrt{144} = 12 \\ \sqrt{169} = 13 \\ \sqrt{196} = 14 \\ \sqrt{225} = 15 \\ [/tex]
[tex]b)3 < \sqrt{15} < 4 \\ 7 < \sqrt{50} < 8 \\ 4 < \sqrt{23} < 5 \\ 6 < \sqrt{37} < 7 \\ 8 < \sqrt{70} < 9 \\ 9 < \sqrt{85} < 10 \\ 10 < \sqrt{120} < 11 \\ 13 < \sqrt{194} < 14[/tex]
Zad 8
Wypisuje to co trzeba podkreślić
[tex]a)( \sqrt{7} ) {}^{2} \\ \sqrt{49} \\ \sqrt{7} \times \sqrt{7 } \\ \sqrt{ {7}^{2} } [/tex]
[tex]b) \sqrt{23} \times \sqrt{23 } \\ ( \sqrt{23} ) {}^{2} \\ \sqrt{ {23}^{2} } \\ \sqrt[3]{23} \times \sqrt[3]{23} \times \sqrt[3]{23} \\ \sqrt[3]{ {23}^{3} } [/tex]
Zad 9
[tex]a)6 \sqrt{5} \times \sqrt{5} = \\ 6 \times \sqrt{5} \times \sqrt{5} = \\ 6 \times 5 = 30[/tex]
[tex]b) \sqrt{6} \times 4 \sqrt{6} = \\ 4 \times \sqrt{6} \times \sqrt{6} = \\ 4 \times 6 = 24[/tex]
[tex]c) \sqrt{7} \times 2 \sqrt{7} = \\ 2 \times \sqrt{7} \times \sqrt{7} = \\ 2 \times 7 = 14[/tex]
[tex]d)2 \sqrt{3} \times 5 \sqrt{3} = \\ 2 \times 5 \times \sqrt{3} \times \sqrt{3} = \\ 10 \times 3 = 30[/tex]
[tex]e) - 4 \sqrt{2} \times 3 \sqrt{2} = \\ - 4 \times 3 \times \sqrt{2} \times \sqrt{2} = \\ - 12 \times 2 = - 24[/tex]
[tex]f) - 3 \sqrt{5} \times 2 \sqrt{5} = \\ - 3 \times 2 \times \sqrt{5} \times \sqrt{5} = \\ - 6 \times 5 = - 30[/tex]
Jest na pewno dobrze liczę na naj:)
