Odpowiedź :
[tex]dane:\\m = 80 \ kg\\h = 1,5 \ m\\t = 2 \ s\\g = 10\frac{N}{kg}\\szukane:\\P = ?\\\\W = E_{p} = mgh\\\\P = \frac{W}{t}\\\\P = \frac{mgh}{t}\\\\P = \frac{80 \ kg\cdot10\frac{N}{kg}\cdot1,5 \ m}{2 \ s}\\\\P = 600 \ W[/tex]
[tex]dane:\\m = 80 \ kg\\h = 1,5 \ m\\t = 2 \ s\\g = 10\frac{N}{kg}\\szukane:\\P = ?\\\\W = E_{p} = mgh\\\\P = \frac{W}{t}\\\\P = \frac{mgh}{t}\\\\P = \frac{80 \ kg\cdot10\frac{N}{kg}\cdot1,5 \ m}{2 \ s}\\\\P = 600 \ W[/tex]