Liczymy długości odcinków AB, BC I AC
AB
[tex] \sqrt{(14 + 11)^{2} + {(2 - 2)}^{2} } = \sqrt{ {25}^{2} } = 25[/tex]
BC
[tex] \sqrt{ {( - 2 - 14)}^{2} + {(14 - 2)}^{2} } = \sqrt{( - 16)^{2} + {12}^{2} } = \sqrt{256 + 144} = \sqrt{400} = 20[/tex]
AC
[tex] \sqrt{ {( - 2 + 11)}^{2} + {(14 - 2)}^{2} } = \sqrt{ {9}^{2} + {11}^{2} } = \sqrt{81 + 121} = \sqrt{202}[/tex]
Obwód:
[tex]25 + 20 + \sqrt{202} = 45 + \sqrt{202} [/tex]
