[tex](3^3)^5=3^{3\cdot5}=3^{15}\\\\9^7=(3^2)^7=3^{2\cdot7}=3^{14}\\\\3^{3^2}=3^{3\cdot3}=3^9\\\\3^{2^3}=3^{2\cdot2\cdot2}=3^8\\\\Zatem:\\\\3^{2^3}<3^{3^2}<9^7<(3^3)^5[/tex]
