Zad 2
[tex] {3}^{4} + {3}^{5} + {3}^{6} = {3}^{4} \times (1 + {3}^{1} + {3}^{2} ) = {3}^{4} \times (1 + 3 + 9) = {3}^{4} \times 13[/tex]
Odpowiedź B
zad. 2
[tex]( - 1 \times \frac{1}{3} )^{2} = ( - \frac{4}{3} )^{2} = \frac{16}{9} = 1 \times \frac{7}{9} [/tex]
odpowiedź B
