Odpowiedź:
Zad. 33
[tex]a)2 \sqrt{2} + 8\sqrt{2} - 9 \sqrt{2} = 1 \sqrt{2} [/tex]
[tex]b)10 \sqrt{2} - 6 \sqrt{2} + \sqrt[3]{2} = 4 \sqrt{2} + \sqrt[3]{2} [/tex]
[tex]c)4 \sqrt{2} - 3 \sqrt{2} - 2 \sqrt{2} = - 1 \sqrt{2}[/tex]
Zad.34
[tex]a)2 \times 6 - 4 \times 4 \sqrt{2} + 2 \times 9 = 12 + 16 \sqrt{2} + 18 = 30 - 16 \sqrt{2} [/tex]
[tex]b)3 \times 5 \sqrt{3} + 2 \times 9 \sqrt{3} - 5 \times 25 = 15 \sqrt{3} + 18 \sqrt{3} - 125 = 33 \sqrt{3} - 125[/tex]
[tex]c)2 \times 5 + 2 \times 3 \sqrt{2} - 5 \sqrt{2} = 10 + 6 \sqrt{2} - 5 \sqrt{2} = 10 + 1\sqrt{2} [/tex]
