Zapisz w postaci jednej potęgi.
a) 32 ⋅ 2^4 ⋅ 2^6
b) 27 ⋅ 3^10 : 3^6
c) 128 ⋅ 8 : 2^7



Odpowiedź :

10days

a) [tex]32 * 2^4 * 2^6 = 2^5 * 2^4 *2^6 = 2^{5+4+6} = 2^{15}[/tex]

b) [tex]27 * 3^{10} : 3^6 = 3^3 * 3^{10} : 3^6 = 3^{3+10-6} = 3^7[/tex]

c) [tex]128 * 8 : 2^7 = 2^7 * 2^3 : 2^7 = 2^{7+3-7} = 2^3[/tex]

Odpowiedź:

[tex]a) \: 32 \times {2}^{4} \times {2}^{6} = {2}^{5} \times {2}^{4} \times {2}^{6} = {2}^{9} \times {2}^{6} = {2}^{15} [/tex]

[tex]b) \: 27 \times 3 {}^{10} \div {3}^{6} = {3}^{3} \times {3}^{10} \div {3}^{6} = {3}^{13} \div {3}^{6} = {3}^{7} [/tex]

[tex]c) \: 128 \times {8}^{} \div {2}^{7} = {2}^{7} \times {2}^{3} \div {2}^{7} = {2}^{10} \div {2}^{7} = {2}^{3} [/tex]

Pozdrawiam.