[tex]dane:\\m = 5 \ kg\\E_{p} = 2,4 \ kJ = 2 \ 400 \ J\\g = 10\frac{N}{kg}\\szukane:\\h = ?\\\\Rozwiazanie\\\\E_{p} = m\cdot g\cdot h \ \ /:(m\cdot g)\\\\h = \frac{E_{p}}{m\cdot g}\\\\h = \frac{2400 \ J}{5 \ kg\cdot10\frac{N}{kg}} = \frac{2400 \ N\cdot m}{50 \ N} = 48 \ m[/tex]
Odp. Na wysokości 48 m.
