Odpowiedź :
[tex]f(x) = a(x-p)^2+q\\a = -0,5\\W = (p;q)\\\\W = (5; 6)\\f(x)=-0,5(x-5)^2+6\\f(x)=-0,5(x^2-10x+25)+6\\f(x)=-0,5x^2+5x-12,5+6\\f(x)=-0,5x^2+5x-6,5[/tex]
[tex]y=a(x-p)^2+q\\\\W=(p,q)\\\\a=-0,5 \ i \ W=(5,6)\\\\y=-0,5(x-5)^2+6\\\\y=-0,5(x^2-10x+25)+6\\\\y=-0,5x^2+5x-12,5+6\\\\\huge\boxed{y=-0,5x^2+5x-6,5}[/tex]