[tex]a) \ (3x^{2}+2x) - (-x^{2}+6) = 3x^{2}+2x+x^{2}-6 = 4x^{2}+2x-6\\\\b) \ (2x-y)-(x-2y) = 2x-y -x + 2y = x+y[/tex]
Odpowiedź:
(3x²+2x) - (-x²+6)=
3x*3x+2x-[-x*x+6]=
9x+2x -2x + x+6=
11x-2x + x+6=
10x+6=
10x=6
10x=6I;10
x=6/10
(2*x-y)-(x-2*y) = y+x
y+x