Odpowiedź:
[tex]sin135^{o} - cos150^{o} = sin(180^{o}-45^{o})-cos(180^{o}-30^{o}) = sin45^{o} - (-cos30^{o}) =\\\\=\frac{\sqrt{2}}{2}-(-\frac{\sqrt{3}}{2}) = \frac{\sqrt{2}+\sqrt{3}}{2}[/tex]
