[tex]dane:\\F_1 = 50 \ N\\S_1 = 0,25 \ m^{2}\\S_2 = 1 \ m^{2}\\szukane:\\F_2 = ?\\\\Z \ prawa \ Pascala\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}=p \ \ (constans)\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}\\\\F_2\cdot S_1= F_1\cdot S_2 \ \ /:S_1\\\\F_2 = F_1\cdot\frac{S_2}{S_1}\\\\F_2 = 50 \ N\cdot\frac{1 \ m^{2}}{0,25 \ m^{2}} = 200 \ N\\\\\\p_2 = \frac{F_2}{S_2}\\\\p_2 = \frac{200 \ N}{1 \ m^{2}} = 200 \ Pa[/tex]
