Odpowiedź:
metan CH4
etan C2H6
propan C3H8
butan C4H10
pentan C5H12
heksan C6H14
heptan C7H16
oktan C8H18
nonan C9H20
dekan C10H22
Wyjaśnienie:
wzór ogólny alkanów (CnH2n+2)
metan CH4 n = 1
etan C2H6 n = 2
propan C3H8 n = 3
butan C4H10 n = 4
pentan C5H12 n = 5
heksan C6H14 n = 6
heptan C7H16 n = 7
oktan C8H18 n = 8
nonan C9H20 n = 9
dekan C10H22 n = 10