Odpowiedź:
[tex]a)\ \ 8\sqrt{6}-5\sqrt{6}=(8-5)\sqrt{6}=3\sqrt{6}\\\\\\b)\ \ \sqrt{66}\cdot\sqrt{1\frac{5}{6}}=\sqrt{66\cdot1\frac{5}{6}}=\sqrt{\not66^1^1\cdot\frac{11}{\not6_{1}}}=\sqrt{11*11}=\sqrt{11^2}=11\\\\\\c)\ \ \sqrt{700}+8\sqrt{7}=\sqrt{100\cdot7}+8\sqrt{7}=10\sqrt{7}+8\sqrt{7}=18\sqrt{7}\\\\\\d)\ \ 5\sqrt{35}\cdot\frac{1}{7}\sqrt{7}=5\cdot\frac{1}{7}\cdot\sqrt{35\cdot7}=\frac{5}{7}\cdot\sqrt{245}=\frac{5}{7}\sqrt{49\cdot5}=\frac{5}{\not7}\cdot\not7\sqrt{5}=5\sqrt{5}[/tex]
[tex]e)\ \ \left(\dfrac{3\sqrt{21}}{7}\right)^2=\dfrac{3^2\cdot(\sqrt{21})^2}{7^2}=\dfrac{9\cdot\not21^3}{\not49_{7}}=\dfrac{27}{7}=3\dfrac{6}{7}[/tex]
