1.
[tex]dane:\\V_1 = 0,01 \ m^{3}\\T_1 = 300 \ K\\V_2 = 0,02 \ m^{3}\\szukane:\\T_2 = ?\\\\\frac{V_1}{T_1} = \frac{V_2}{T_2} \ - \ przemiana \ izobaryczna\\\\V_1\cdot T_2 = V_2 \cdot T_1 \ \ /:V_1\\\\T_2 = \frac{V_2}{V_1}\cdot T_1}\\\\T_2 = \frac{0,02 \ m^{3}}{0,01 \ m^{3}}\cdot 300 \ K = 600 \ K[/tex]
2.
[tex]dane:\\p_1 = 2 \ MPa\\T_1 = 0^{o}C = (0+273) \ K = 273 \ K \ - \ temperatura \ w \ zimie\\T_2 = 30^{o}C = (30 + 273) \ K = 303 \ K \ - \ temperatura \ w \ lecie\\szukane:\\p_2 = ?\\\\\frac{p_1}{T_1} = \frac{p_2}{T_2} \ - \ przemiana \ izohoryczna\\\\p_2 \cdot T_1 = p_1\cdot T_2 \ \ /:T_1\\\\p_2 = p_1\cdot\frac{T_2}{T_1}\\\\p_2 = 2 \ MPa \cdot\frac{303 \ K}{273 \ K} \approx 2,22 \ MPa[/tex]
3.
[tex]dane:\\V_1 = 6 \ cm^{3}\\p_1 = 1000 \ hPa\\V_2 = 6 \ cm^{3}-1 \ cm^{3} = 5 \ cm^{3}\\T_1 = T_2\\szukane:\\p_2 = ?\\\\\frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2}\\\\T_1 = T_2\\\\\frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_1}\\\\p_1V_1 = p_2V_2 \ \ /:V-2\\\\p_2 = p_1\cdot\frac{V_1}{V_2}\\\\p_2 = 1000 \ hPa \cdot\frac{6 \ cm^{3}}{5 \ cm^{3}} = 1200 \ hPa[/tex]
